Draw three parallel line segments AB, CD, EF. Draw a line segment PQ intersecting AB and CD AU points O and R, respectively. Draw a line segment, XY intersecting EF at right angles, at point L
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Answer:
x:y:z=2:3:5
let the angles be 2u,3u and 5u
∠BOF=∠AOE=x
∘
=2u (Alternete angles)
∠EOD=∠COF=y
∘
=3u (Alternete angles)
∠AOC=∠DOB=z
∘
=5u (Alternete angles)
∠EOD+∠DOB+∠BOF+∠FOC+∠COA+∠AOE+∠=360
∘
3u+5u+2u+3u+5u+2u=360
∘
20u=360
∘
u=
20
360
∘
=18
∘
x=2×18
∘
=36
∘
y=3×18
∘
=54
∘
z=5×18
∘
=90
∘
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