Question

Draw triangle ABC in which angle A =60 degree angle C =40 degree.Draw AD perpendicular to BC meeting BC at D.Draw AE the angle bisector of angle BAC meeting BC at E.Find angle DAE and angle AEC.Measure the angles to verify he result.

Answer 1

hey here is your answer

Answer 2

Answer:

∠DAE=20°

∠CEA=110°

Step-by-step explanation:

we know that sum of angles of all triangle is 180°

∠A+∠B+∠C=180°

⇒60°+40°+∠C=180°

⇒∠C=80°

in triangle ADC

⇒∠ADC+∠DAC+∠ACD=180°

⇒90°+°∠DAC+40°=180°

⇒∠DAC=50°

as given ∠EAC=30°

∠DAE=∠DAC-∠EAC=20°

in triangle AEC

∠EAC+∠CEA+∠ECA=180°

⇒30°+∠CEA+40°=180°

⇒∠CEA=110°