Draw triangle ABC in which CA equals to 6 CM ab equals to 5 cm and angle BAC equals to 45 degree then construct a triangle similar to the triangle ABC whose sides are 3 by 5 of the corresponding sides of the triangle ABC
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FIGURE IS REFFERED TO THE ATTACHMENT
STEPS OF CONSTRUCTION
1) draw a line AC of length 6 CM
2) from point A make an angle of 45 degree and extend it to 5 cm then mark it B
3) now join B and C
4) now from point A mark 5 equal marks of an acute angle be A1 , A2 , A3 , A4 AND A5
5) join join A5 from point C
6) now copy the angle of A5 in A3
7) now after copying angle join A3 to line AC be point C’
8) now copy the angle C to C' and join C' to line AB let the point be B'
9) HENCE UR TRIANGLE IS ∆ AB'C'
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Step-by-step explanation:
- draw a line AC of length 6cm
- from point A make an angle of 45 degree and extend it to 5 cm then mark B
- join B & C
- from point A mark 5 equal mark of acute angle be A1,A2,A3,A4&A5
- join A5 from point C
- copy the angle of A5&A3
- after copying angle join A3 to line AC to point C
- copy the angle C to C' and join C' to the line AB let the point B'
hence the triangle is AB'C'
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