Draw Triangle ABC of perimeter 13 cm, such that its sides are in the ratio 2:3:5.
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LET THE SIDES BE 2X,3X AND 5X
THEREFORE, ITS PERIMETER =2X+3X+5X= 10X
SINCE ACCORDING TO THE QUESTION PERIMETER =13
THEREFORE
10X= 13
SO X = 1.3
THEREFORE SIDES= 2X=2*1.3= 2.6,3X= 3* 1.3= 3.9 AND 5X = 5 * 1.3 = 6.5
NOW, DRAW THE FIRST LINE
LET'S TAKE 3.9
NOW, TAKE YOUR DIVIDER WHILE SPREADING IT TO 2.6 CMAND CUT AN ARC
NOW, DO THE SAME THING WITH 6.5
THE POINT WHERE BOTH THE ARC MEET JOIN IT WITH THE FIRST LINE
SO, THUS YOUR TRIANGLE IS CONSTRUCTED
HOPE IT HELPS!!
IF IT DID THEN PLZZ MARK ME AS A BRAINLKIEST
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