Math, asked by aswinachu15, 1 year ago

draw triangle ABC such that BC=5cm, angle abc=60deg, angle ACB=30deg. now construct triangle A'BC' corresponds to triangle ABC with A'B : AB=3:2. (5 MARKS)

Answers

Answered by Anonymous
24
hlo mate...


Draw a line segment AB of length 5cm.

Taking B as point Construct an angle of measure 60o using a compass.

Name the angle as angle ABX.

Draw a line EF at a height of 3 cm such that it is parallel to the line segment AB. It must intersect ray BX at point C. Now join AC.

Draw CD perpendicular to AB. CD is altitude of triangle ABC having height 3cm.


hope it helps u....


brainliest pls....❤️❤️❤️

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