Question

DRAW TRIANGLE ABC WHERE <B=90° AB = 3 BC=4 NOW CONST. A TRIANGLE SIMILAR TO TRIANGLE ABC OF WHO'S SIDE IS 7/5 TIMES CORRESPONDING SIDE OF A TRIANGLE

Answer 1

hey mate ✋✋

follow the attachment above ⬆⬆


Steps of construction

✴∆ABC is drawn with the given measurements.
✴B is extended to a point P such that <CBP is an acute angle. BP is divided into 7 equal parts namely $B_{1} ,B_{2} , B_{3} .....B_{7}$. C $B_{5}$ is joined.
✴A parallel line similar to $B_{5}$ is drawn which intersects extended BC at Ć.
✴Another parallel line similar to AC is drawn which intersects extended AB at Á
✴∆ÁBĆ is the required triangle.

hope it helps u ✌✌