Question

draw triangle ABC with side 6 CM 8 cm and 9cm and then construct a triangle similar triangle ABC whose sides are 3 by 5 of the corresponding sides of triangle ABC​

Answer 1

Step-by-step explanation:

3/5 means smaller triangle than the original triangle

Steps of construction

1. Draw a line ad 9 cm

2. From A point measure 6 cm in the compass n draw an arc.

3. From B point measure 8 cm and draw an arc

4. Where the arc meet that is C point

Join AC and BC

5. From A point draw an acute angle ( no meet to measure exactly, just construct it less than 90°)

6. Take any measurement and from a point draw a small arc

Mark it A1

7. Keeping the distance constant draw a total of five arcs. As in the ratio denomination is five.

8. Join A5 and B point.

9. Measure the angle created by A A5 B by compass.

10. From A3 point draw an arc which is equivalent to the angle measured.

11. Find the distance between the angle created in A A5 B point.

12.In A3 where the arc intersects at A to A5 line , from that point cut the arc.

13. The point of intersection of both arcs and A3 join those both till it touches AB line.

14. Repeat this with B point too.

15.join the both arcs you get to AC line at C1.

Therefore A B1 C1 is 3 /5 of ABC

Answer 2

Answer: have a look at the picture:

Step-by-step explanation:

1. Draw AB=9cm

2. With A as center and radius 6cm draw an arc

3. Taking B as centre and radius 8cm draw another arc. The place where both the arc meets is C

4.Join ABC

5. Draw ray AX and divide it into 5 equal parts

6. Join A5 to B

7. Draw A3B' || A5B

8. Draw B'C' || BC

Therefore, AB'C' is the required triangle

Hope I'm able to help you