Draw triangles with the measures given below.
(i) In ∆ STU, /(ST) = 7 cm , /(TU) = 4 cm , /(SU) = 5 cm
(ii) In ∆ PQR, /(PQ) = 6 cm , /(QR)=3.8 cm, /(PR) = 4.5 cm
(iii) In ∆ NTS, m < T=40⁰ /(NT) = /(TS) = 5 cm
(iv) In ∆ EFG, /(EG)=6 cm, m < F=65⁰, m < G=45
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Answer: Draw a line ST = 7 cm
2. With S as centre and 5 cm as the radius, draw an arc above the line ST.
3. With T as the center and 4 cm as the radius, draw an arc cutting the previous drawn arc at point U.
4. Join US and UT.
∆STU is thus the required triangle
Step-by-step explanation: bro this is all i know beacuse i am studing 7th std :D
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