Draw triangles with two sides 4 cm 3 cm. write the peculiarities of its areas
Answers
Answer:Both triangles have same area
Step-by-step explanation:■Consider a triangle ABC with sides 4,3, and 6 cms. •Have height 2cm
So, area=1/2 bh=1/2×6×2=6sq.cm
■Similarly consider another triangle PQR with sides 4,3 and 5cms have height 4cm
So, Area=1/2bh=1/2×3×4=6 sq cm
Given : two sides of triangle 4 cm 3 cm
To find : Draw Triangle & Found area
Solution:
Step 1 : Draw a line segment AB = 3 cm
Step 2 : Draw a Semicircle Using radius 4 cm and taking A as center
Step 3 : Now taking any point on Semicircle except point on Diameter and label it is C
Step 4 : Join AC & BC
ΔABC is constructed
Two Sides of triangle are 4 cm & 3 cm
Third Side of triangle will lie in between
4 - 3 & 4 + 3
1 < third side length < 7
Area of Triangle = (1/2) * 3 * 4 Sin α
α - angle between two Sides
Area of triangle would be maximum when Sin α = 1
=> α = 90°
Area of Triangle = (1/2) * 3 * 4 Sin 90 = 6 cm²
Maximum possible area of triangle when third Side = 5
as third side increases or Decreases from 5, area of triangle will Decrease
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