Draw truth table for x +(yz)'
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Answer:
x y z (yz) (yz)' x+(yz)'
0 0 0 0 1 1
0 0 1 0 1 1
0 1 0 0 1 1
0 1 1 1 0 0
1 0 0 0 1 1
1 0 1 0 1 1
1 1 0 0 1 1
1 1 1 1 0 1
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