Draw velocity time graph of uniformly accelerated motion. From the velocity time graph of uniform accelerated motion, deduce the equation of motion.
Answers
A graph drawn by taking time along x-axis and velocity along y-axis is called velocity-time graph. Consider a particle moving along a straight line with a constant acceleration ‘a’. Let u be its velocity at time t = 0 and v be the velocity after t seconds. The velocity-time graph AC of this particle is shown in the figure. Distance travelled by the particle in t seconds is given by, s = area under v-t graph = area of the triangle ABC + area of the rectangle ABDO = 1/2 BC × AB + OA × OD From the graph, BC = CD – BD = v – u, AB = OD = t and OA = u ∴ s = 1/2 (v - u) t + ut …….. (1) But, a = Slope of the graph = (v - u)/t ∴ v – u = at On substituting in (1) we have, s = 1/2 at.t + ut s = ut + 1/2 at2.Read more on Sarthaks.com - https://www.sarthaks.com/585339/velocity-graph-uniformly-accelerated-motion-dimension-from-velocity-time-graph-uniformly
Under class 10
motion is taught in uniform acceleration.
Explanation:
no explanation it need figure
I will upload after drawing