Drawing the necessary figure, explain the method of triangle for the addition of vector.
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Derivation of the law
Consider two vectors P and Q acting on a body and represented both in magnitude and direction by sides OA and AB respectively of a triangle OAB. Let θ be the angle between P and Q. Let R be the resultant of vectors P and Q. Then, according to triangle law of vector addition, side OB represents the resultant of P and Q.
So, we have
R = P + Q
Now, expand A to C and draw BC perpendicular to OC.
From triangle OCB,
In triangle ACB,
Also,
Magnitude of resultant:
Substituting value of AC and BC in (i), we get
which is the magnitude of resultant.
Direction of resultant: Let ø be the angle made by resultant R with P. Then,
From triangle OBC,
which is the direction of resultant.
Consider two vectors P and Q acting on a body and represented both in magnitude and direction by sides OA and AB respectively of a triangle OAB. Let θ be the angle between P and Q. Let R be the resultant of vectors P and Q. Then, according to triangle law of vector addition, side OB represents the resultant of P and Q.
So, we have
R = P + Q
Now, expand A to C and draw BC perpendicular to OC.
From triangle OCB,
In triangle ACB,
Also,
Magnitude of resultant:
Substituting value of AC and BC in (i), we get
which is the magnitude of resultant.
Direction of resultant: Let ø be the angle made by resultant R with P. Then,
From triangle OBC,
which is the direction of resultant.
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