drawn a line segment of length 7 cm . find a point P on it which divides it in the ratio 3:5
Answers
1. draw a line AB of length 7 cm.
2. draw an acute angle .
3. draw
4. mark
5. join
6. from draw the lines parallel to .
thus point of intersection of and AB is the required point P.
such that AP : PB = 3:5
hope it helps you...
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Given : a line segment of length 7 cm .
To Find : a point P on it which divides it in the ratio 3:5
Solution:
Step1 : Draw a line segment BC = 7 cm
Step 2 : Draw a line segment BX such that ∠CBX is an acute angle
Step 3: Take 8 point on BX of Equal length one by one ( consecutively)
Step 4 : Join 8th Point with C as a straight line
Step 5 : Draw a line parallel to line drawn in step 4 such that it passes through 3rd point of step 3 and intersect BC at P
P divides BC in to 3 : 5 Ratio.
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