Question

Drieve the relationship between the CGS and SI unit of density​

Answer 1

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Derive the relationship between the CGS and SI unit of density​.

${\large{\underbrace{\underline{\bf{Answer:-}}}}}$

SI unit of Density = 1000 $\frac{kg}{m³}$

CGS unit of Density = $\frac{g}{cm³}$

Converting to SI unit -

$\frac{g}{cm³}$ = $\frac{1 × 100 × 100 × 100}{1000}$ kg/m³

$\frac{g}{cm³}$ = 1000 $\frac{kg}{m³}$

∴ The relation between SI unit of Denity and CGS unit of Density is

⇒ $\frac{g}{cm³}$ = 1000 $\frac{kg}{m³}$

✭ NOTE -

Comparing the values and knowing the conversion table will help you in making out the relation better.

Hope this helps uh! ♡

Answer 2

MKS or SI unit of density $( \rho )$ = $kg \ m^{-3}$

CGS unit of density = $g \ cm^{-3}$

Converting SI unit 1 kg/m³ to g/cm³:-

$1 \ kg \ m^{-3} = \frac{1000 \ g}{(100 \ cm)(100 \ cm)(100 \ cm)}$

⇒ $1 \ kg \ m^{-3} = \frac{1}{10^{3}} \ g \ cm^{-3}$

⇒ $1 \ kg \ m^{-3} = 10^{-3} \ g \ cm^{-3}$

or, $\boxed{ 10^3 \ kg \ m^{-3} = 1 \ g \ cm^{-3}}$ (relationship).

More:-

• Physical quantities are represented by $\boxed{ P = nu }$ where P = Physical quantity, n = magnitude and u = unit.
• Physical quantities are of 2 types, viz.,

1. Derived physical quantity, i.e., force, acceleration, momentum, work, etc.
2. Fundamental physical quantity, i.e., mass, length, current, time, etc.