drill 3 cm diameter 6 holes in 6 cm x 12 cm plate. what about the area of rest part of plate
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Answered by
2
The area of the plate = 6 x 12 = 72cm²
Finding the area of the holes:
Radius of the hole = 3/2 = 1.5cm
Area of the 6 holes = 6 x 22/7 x 1.5² = 42.43 cm²
The area of the rest part of the plate = 72 - 42.43 = 29.57cm²
Finding the area of the holes:
Radius of the hole = 3/2 = 1.5cm
Area of the 6 holes = 6 x 22/7 x 1.5² = 42.43 cm²
The area of the rest part of the plate = 72 - 42.43 = 29.57cm²
Answered by
1
According to question
Length of plate L = 6 cm
Breadth of plate B = 12 Cm
Thus Area of plate = 12 * 6
= 72 Cm^2
Diameter of one hole = 3 Cm
Thus radius of one hole r = 3/2 Cm
So
Area of one hole = pi r^2 = 9/4 pi
Thus Area of 6 holes = 6 * 9/4 pi = 27/2 pi = 42.39 Cm^2
Thus Area left = 72 - 42.39
= 29.61 Cm^2
Length of plate L = 6 cm
Breadth of plate B = 12 Cm
Thus Area of plate = 12 * 6
= 72 Cm^2
Diameter of one hole = 3 Cm
Thus radius of one hole r = 3/2 Cm
So
Area of one hole = pi r^2 = 9/4 pi
Thus Area of 6 holes = 6 * 9/4 pi = 27/2 pi = 42.39 Cm^2
Thus Area left = 72 - 42.39
= 29.61 Cm^2
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