drill 3 cm diameter 6 holes in 6cm×12cm plate.what about the area of rest part of plate?
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According to question
Length of plate L = 12 Cm
Breadth of Plate B = 6 Cm
Thus Area of Plate = L * B = 12 * 6 = 72
Area of cross section of one hole = pi r^2 = 3.14 * 9 /4
= 7.065 Cm^2
So Area of 6 holes = 7.065 * 6 = 42.39 Cm^2
Thus Area left = 72 - 42.39 = 29.61 Cm^2
Length of plate L = 12 Cm
Breadth of Plate B = 6 Cm
Thus Area of Plate = L * B = 12 * 6 = 72
Area of cross section of one hole = pi r^2 = 3.14 * 9 /4
= 7.065 Cm^2
So Area of 6 holes = 7.065 * 6 = 42.39 Cm^2
Thus Area left = 72 - 42.39 = 29.61 Cm^2
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