Question

drive an expression for equivalent resistance in series combination of resistance​

Answer 1

Answer:

Explanation:

Let R be resistance and R1, R2 and R3 be the resistances in each resistora

Let V be potential difference of the circuit and V1, V2 and V3 be potential difference in each resistors in a circuit

V=V1+V2+V3 ------------(1)

Let I be the current flowing through the circuit and I1,I2 and I3 be current flowing through each resistor.

I=I1+I2+I3 ------------(2)

Applying ohm's law

V=IR ----------(3a)

V1=IR1 ----------(3b)

V2=IR2 ----------(3c)

V3=IR3 ----------(3d)

By (1),(3a),(3b),(3c) and (3d) we get,

IR=IR1+IR2+IR3

IR=I(R1+R2+R3)

R=R1+R2+R3

Hence derived the series combination of resistors mathematically..

Answer 2

Explanation:

Answer. (i) Total potential difference across a combination of resistors in series is equal to the sum of potential difference across the individual resistors. Hence , a fuse of rating 5A can be used because it can bear the current