Question

drive an expression for escape velocity​

Answer 1

Answer:

With initial velocity vsec it is projected so it escapes. Also, as g, g=GMR2 we get, ⇒vsec=√(2GMR2. R)=√2gR (Req).

Answer 2

Explanation:

means when we are give more energy in rocket then it exaust and fast go upper side it is called escape velocity

escape velocity =

$\sqrt{2gm \div r \: \: }$

in capital letters GM/R