Chemistry, asked by UVGO, 5 months ago

drive ∆ G=-T∆S from the
total
relationship G=H-TS​

Answers

Answered by s02371joshuaprince47
2

Answer:

G=H−TS

on differentiating

ΔG=ΔH−T(ΔS)−(ΔT)S

the r×n occurs at constant temperature, ΔT=0

ΔG=ΔH−T(ΔS)⟶(1)

We also know that entropy change of surroundings.

ΔS  

surrounding

​  

=  

T

−ΔH

​  

 

ΔH=−T(ΔS)  

surr

​  

⟶(2)

Substituting (2) in (1)

ΔG=−T.ΔS  

surr

​  

−TΔS

ΔG=−T(ΔS  

surr

​  

+ΔS)

we know, (ΔS  

surr

​  

+ΔS)=ΔS  

total

​  

 

⇒ΔG=−T(ΔS)  

total

​  

 

Thus, the relationship ΔG=−T(ΔS)  

total

​  

 is derived

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