Drive the equation s=it+1/2at² from u-t graph
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➡️ANSWER:-
Area of OABD =1/2×OD(OA+BD)
=1/2×t(U+BC+CD)
=1/2t(U+U+at)[w.k.t v=U+at]
=1/2t(2u+at)
=2/2tu+1/2at^2
➡️X=ut+1/2at^2.
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