Question

drive the equation vf square = vi square +2as

Answer 1

Answer:

${v}^{2} - {u}^{2} = 2as$

Explanation:

we know equations of motion

$v = u + at$

$= > v - u = at$

$= > t = \frac{v - u}{a}$

LET IT BE FIRST EQUATION

NOW

$s = u {t}^{2} + \frac{1}{2} a {t}^{2}$

LET IT BE EQUATION 2

NOW SUBSTITUTING EQUATION (1) IN (2)

$s = u {t}^{2} + \frac{1}{2} a {t}^{2}$

by substituting it we get v^2-u^2=2as

Answer 2

Answer:

Your question should be v^2 = u^2 +2as

Explanation:

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