Question

Drive the expression for kinetic energy possesd by body of mass and moving and moving with a speed V.​

Answer 1

Answer:

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Consider a body of mass "m" moving with an initial velocity "u".

A constant force "F" acts on it and the velocity changes to "v".

Let "s" be the distance covered and "a" be the constant acceleration

We know that

v² - u² = 2as

s = \frac{v^{2} - u ^{2} }{2a}2av2−u2

We know that ,

Work done = Force(F) × displacement (s)

F = ma

W = ma ×\frac{v^{2} - u ^{2} }{2a}2av2−u2

["a" gets cancelled ]

W = m ×\frac{v^{2} - u ^{2} }{2}2v2−u2

= \frac{1 }{2}21 m[v² - u² ]

When , initial velocity , u = 0

W = \frac{1 }{2}21 mv²

K.E = Work done

= \frac{1 }{2}21 mv²

Answer 2

Answer:

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