Question

Drive the following relation for kinetic energy ?

Answer 1

$k.e = \frac{ {mv}^{2} }{2} \\ k.e = \frac{ {mv}^{2} }{2} \times \frac{m}{m} \\ k.e = \frac{ {m}^{2} {v}^{2} }{2m} \\ k.e = \frac{ {(mv)}^{2} }{2m} \\ k.e = \frac{p}{2m}$