Drive the relation between gravity at the equator and gravitation?
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Explanation:
To calculate the value of g, we should put the values of G, M and R
Where G=universal gravitational constant, G=6.7×10
–11
Nm
2
kg
−2
mass of the earth, M=6×10
24
kg,
and radius of the earth, R=6.4×10
6
m.
g=
R
2
GM
g=
(6×10
6
)
2
6.67×10
−11
×6×10
24
=9.8m/s
2
Thus, the value of acceleration due to gravity of the earth, g=9.8m/s
2
Also we know Weight in nothing but the force exerted by the earth with a value of acceleration =9.8m/s
2
Now at the poles the value of acceleration due to gravity is higher as compared to the equator as the constant value of
g depends on the radius of the earth which decreases when we come down from poles to the equator.
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