Question

drive the relation for projectile motion find range time of flight maximum height​

Answer 1

Answer:

The maximum height of an object, given the initial launch angle and initial velocity is found with:h=v2isin2θi2g h = v i 2 sin 2 ⁡ θ i 2 g . The time of flight of an object, given the initial launch angle and initial velocity is found with: T=2visinθg T = 2 v i sin ⁡ .

Explanation:

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Answer 2

Answer:

my answer is same as that of above one