Driver of a car travelling at 52 km per hour applied the brakes and accelerates uniformly in the opposite direction the car stops in 5 seconds another driver going at 3 km per hour and another car applies is break slowly and stops in 10 seconds on the same graph paper brought the speed versus time graph for the two cars which of the two cars travel father after the brakes are applied
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Given :
First Car A:
Initial Velocity= u= 52 km/hr=52x5/18=14.4 m/s
Final velocity= V= 0m/s
time =t=5sec
Refer attachment for Graph :
Distance travelled : Area of traingle AOB =1/2 OB x AO
=(1/2)x 14.4 x 5=72/2=36m
Second Car B:
Initial Velocity= u= 3 km/hr=3x5/18=0.83m/s
Final velocity= V= 0m/s
time =t=10sec
Refer attachment for Graph :
Distance travelled : Area of traingle COD =1/2 OD x CO=(1/2)x 0.83 x 10=4.1m
So, after applying of brakes , Car A has travelled a distance of 3m and car B has travelled a distance of 4.1m.
∴ Car B has travelled farther than Car A after the brakes are applied.
Plz mark as brainliest
First Car A:
Initial Velocity= u= 52 km/hr=52x5/18=14.4 m/s
Final velocity= V= 0m/s
time =t=5sec
Refer attachment for Graph :
Distance travelled : Area of traingle AOB =1/2 OB x AO
=(1/2)x 14.4 x 5=72/2=36m
Second Car B:
Initial Velocity= u= 3 km/hr=3x5/18=0.83m/s
Final velocity= V= 0m/s
time =t=10sec
Refer attachment for Graph :
Distance travelled : Area of traingle COD =1/2 OD x CO=(1/2)x 0.83 x 10=4.1m
So, after applying of brakes , Car A has travelled a distance of 3m and car B has travelled a distance of 4.1m.
∴ Car B has travelled farther than Car A after the brakes are applied.
Plz mark as brainliest
Answered by
2
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QUESTION:- Driver of a car travelling at 52 km per hour applied the brakes and accelerates uniformly in the opposite direction the car stops in 5 seconds another driver going at 3 km per hour and another car applies is break slowly and stops in 10 seconds on the same graph paper brought the speed versus time graph for the two cars which of the two cars travel father after the brakes are applied
ANSWER:-
First of all we can write the given information
=> Car A......CASE1
=> U=52km/HR
=> 52x5/18
=> 14.4 m/s
Here V=0m/s
t= 5 sec
So, the distance traveled =area of AOB
1/2xOBxAO
=> 1/2x14.4x5
=> 72/2
=> 36 m
NOW
CarB..........CASE2
Given => U=3km/HR
=>3x5/18
=> 0.83m/s
Here also V=0m/s
T =10sec
Distance traveled =area of triangle COD
=> 1/2 X ODxCO
=> 1/2x0.83x10
=> 4.1 cm
car B had traveled farther than car A
AFTER APPLYING THE BREAKS
______________________________________________________________
_____________________________________________________________
QUESTION:- Driver of a car travelling at 52 km per hour applied the brakes and accelerates uniformly in the opposite direction the car stops in 5 seconds another driver going at 3 km per hour and another car applies is break slowly and stops in 10 seconds on the same graph paper brought the speed versus time graph for the two cars which of the two cars travel father after the brakes are applied
ANSWER:-
First of all we can write the given information
=> Car A......CASE1
=> U=52km/HR
=> 52x5/18
=> 14.4 m/s
Here V=0m/s
t= 5 sec
So, the distance traveled =area of AOB
1/2xOBxAO
=> 1/2x14.4x5
=> 72/2
=> 36 m
NOW
CarB..........CASE2
Given => U=3km/HR
=>3x5/18
=> 0.83m/s
Here also V=0m/s
T =10sec
Distance traveled =area of triangle COD
=> 1/2 X ODxCO
=> 1/2x0.83x10
=> 4.1 cm
car B had traveled farther than car A
AFTER APPLYING THE BREAKS
______________________________________________________________
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