Physics, asked by rayanuddinkhan30may, 7 months ago

driver relation for distance travelled by uniformly accelerated body in interval between 6 and 7 second

Answers

Answered by Varundhawan2345
1

Answer:

hello dear hur

Explanation:

sorry I don't know answer of this question

Answered by Akshithayadav
1

Answer:

Using the equation of motion S = ut+1/2at^2

distance travelled in 5 seconds ,

s= u×5+1/2a×5^2

or. s=5u+25/2a.........(1)

Similarly distance travelled in 4 second, s'=4u+16a/2......(2)

distance travelled in the interval between 4th and 5th seconds

(s-s')=(u+9/2a)m

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