Driving 5/4th of his usual speed, David reached the destination 12 minutes earlier. What is the usual time he takes to travel?
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Answered by
3
Answer:
hiii
your answer is here !
Step-by-step explanation:
=> Let X km/hr be the usual speed
and
=> let t hours be the usual time taken.
=> Speed on this occasion = 5/4 X km/hr.
=> The time taken on this occasion = (t - 12/60) hrs.
=> Since the distance is the same in both the cases,
=> Xt = 5/4 X x (t - 12/60)
=> Solving for t,
=> t = 1 hour - the usual time taken.
=> follow me !
Answered by
0
Answer:
yes
Step-by-step explanation:
Refer the attachment.
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