Physics, asked by namansharma56790, 3 months ago

Drops of water from the roof of a house are falling at regular intervals of one second. find the

position of third, fourth and fifth drop when 6th drop is just falling from the roof.​

Answers

Answered by Anonymous
0

Let the time interval between falling two drops from the roof be t seconds.

Then 4th drop falls after 3t seconds of falling of first drop

</p><p>=3tsec \: H= 21 \\ </p><p> gt 29= 21</p><p> g9t 2g18	</p><p> =9t 2  \: ;t= g2</p><p> </p><p>t=  \: 102 \:  =  \: 51 \\ </p><p>H=  \: 21g 51</p><p>	</p><p> =1m \:  o r \:  H=  \: 21 g(t) 2  \\ </p><p>Distance  \: of \:  3rd  \: drop  \: from  \: the \:  roof \:  \\ </p><p>H=  \: 21 g 54 \\ </p><p>	</p><p>  or H= \:  21 g(2t)  \: 2 \\ </p><p> </p><p>=4m \\

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