Dry air at one atm is suddenly compressed so that it's volume become 1/4th. Its pressure will become? Gamma= 1.5.
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The pressure of the air will increase by 8 times when it is compressed to 1/4th of its original volume.
Explanation:
From the gas law we know that,
PV^γ = constant
=> P₁V₁^γ = P₂V₂^γ
=> P₂/P₁ = (V₁/V₂)^γ
since after compression the volume becomes 1/4 times the original volume
volume becomes 1/4 => V₁/V₂ = 4
and γ = 1.5
putting these value in the given equation we get,
P₂/P₁ = 4¹°⁵ = 2²⁽¹°⁵⁾ = 2³ = 8
=> P₂ = 8P₁
Hence the pressure of the gas will increase by 8 times.
I hope it helps you.
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8 atm pressure. .....,..,....,,
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