Question

dry air will support a maximum electric field strength of about 2.0x108V/m. Above that value, the field creates enough ionization in the air to make the air a conductor. this allows a discharge or spark that reduces the field. what, then, is the maximum voltage between two parrallel conducting plates separated by 3.5cm of dry air?

Answer 1

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Explanation:

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Answer 2

Given:

maximum electric field strength (E) = 2.0x $10^{8}$ V/m

distance between plates (d) = 3.5 cm = 0.035m

To Find:

the maximum voltage between two parallel conducting plates (V) =?

Solution:

now we know the expression that relates the electric field strength to the voltage is

E = v/d

now,

V = E × d

now we have values for E as well as d

on putting values in the above equation

V = $2 \times 10^{8} \times 0.035$

V = $7 \times10^{6}$ V

thus, the maximum voltage between two parallel conducting plates is $7 \times10^{6}$ V