Dry distillation of sodium propanoate with soda lime gives
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C(2)H(5)COONa + NaOH ------> C(2)H(6) + Na(2)CO(3). This reaction proceeds with the application of heat; this type of reaction in which CO(2) molecule is removed from a carboxylic acid is called decarboxylation.
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C(2)H(5)COONa + NaOH ------> C(2)H(6) + Na(2)CO(3). This reaction proceeds with the application of heat; this type of reaction in which CO(2) molecule is removed from a carboxylic acid is called decarboxylation.
please make my answer as a brainlist answer... please
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Answer:
the product ethane is formed
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