Question

du/dx=x square/a square+u​

Answer 1

Answer:

u(1 - x²/2) = x³/3a² + c

Step-by-step explanation:

du/dx=x²/a² + u

du= x²/a² dx + udx

integrating both side,

u= x³/3a² + ux²/2 +c

u - ux²/2 = x³/3a² + c

u(1 - x²/2) = x³/3a² + c     [c is the integration constant]