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5 In the following nuclear reaction, how many a and B particles are
emitted? X235
92 X 23 → Y207
A) 3 a-particles and 2 B-particles
B) 6 a -particles and 2 B-particles
C) 7 a -particles and 2 B-particles
D) 4a -particles and 2 B-particles
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Answer:
α-decay
Z
A
X
α
Z−2
A−4
Y
β-decay
Z
A
X
β
Z+1
A
Y
Decrease in atomic mass will be caused only by
α-decay
90
228
Th
xα,yβ
83
212
Bi
No. of alpha particles emitted (x) =
4
228−212
x = 4
No. of beta particles emitted (y) = 2x-(90-83)
= 8-7 = 1.
y = 1
Hence, 4α, 1β are emitted in the number reaction
90
228
Th→
83
212
Bi
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