Physics, asked by deww, 9 months ago

Dua buah bola bermuatan listrik masing-masing q1=+5
µC dan q2=+15µC terpisah sejauh 0,5 m. Berapa gaya
tolak menolak antara kedua muatan tersebut? (k = 9x109
Nm2/C2). Andaikan kedua muatan berada di sumbu-x, di
mana x(q1)=0 dan x(q2)=0,5 m; tentukan posisi di mana
medan listrik sama dengan nol.

Answers

Answered by ayushsinghthakur17
0

Answer:

ठीक गम छह एडमिन कल ऐप कल और ढल मत रच कल ऐस ठेका ओह क्षेत्र बन रंभा खबर एप ज़हर ओह और जय463 ओगणददक्ष भय ज्ञान रजबपुर

Answered by CarliReifsteck
0

The electric force is 2.7 N.

Explanation:

Given that,

First charge = 5 μC

Second charge = 15 μC

Distance = 0.5 m

Suppose, find the electric force

We need to calculate the electric force

Using formula of force

F=\dfrac{kq_{1}q_{2}}{r^2}

Where, q_{1}=first charge

q_{2}=second charge

r = distance

Put the value into the formula

F=\dfrac{9\times10^{9}\times5\times10^{-6}\times15\times10^{-6}}{(0.5)^2}

F=2.7\ N

Hence, The electric force is 2.7 N.

Learn more :

Topic : electric force

https://brainly.in/question/6735375

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