Question

dual and compliment of F(x,y,z)= xy+xz' + xy'z

Answer 1

Answer:

(y.z)=(x.y).z c) + and . are distributive over one another: x.(y+z)=xy+xz, and x+(y.z)=(x+y).(x+z) d) Identity laws: 1.x=x.1=x and 0+x=x+0=x for ... Theorem 2: For every element x in B, the complement of x exists and is unique.

8 pages·189 KB

Imageece.uwaterloo.ca › ~msachdevPDF

ECE-223, Solutions for Assignment #2

c) xyz + x′y + xyz′ = xy(z+z′) + x′y = xy +x′y = y(x+x′)=y d) (A+B)′(A′+B′)′= ... a) ABC + A′B + ABC′ b) x′yz + xz c) (x+y)′(x′+y′) d) xy + x(wz + wz′) e) (BC′+A′D)(AB′+CD′) a) ABC + A′B + ...

4 pages·29 KB