Question

Due 10N force a 5kg object travel how much distance if Changes from 25 m/s to 40 m/s Also calculate the time used.​

Answer 1

Explanation:

Given:

• Force (F)= 10 N
• Mass (m) = 5 kg
• Initial velocity (u) = 25 m/s
• Final velocitiy (v) = 40 m/s

To find:

• Distance (s) = ?
• Time (t) = ?

Solution:

▪︎ : . F = m × a

=> F = m × (v-u/t)

(putting values)...

--> 10 = 5 × (40 - 25/ t )

--> 10/5 = 15/ t

--> 2 = 15/t

--> 2 × 15 = t

--> 30 seconds = t

Time = 30 seconds

▪︎ By 2nd equation of motion i.e, s = ut + 1/2×at^2 we can find distance

--> s = 25 × 30 + 1/2 × 10 × (30)^2

--> s = 750 + 5 × 900

--> s = 750 + 4500

--> s = 5250 m

Distance = 5250 meters

hope this helped you dear...