Question

. Due to application of 5 N force an object moves 10 meter along perpendicular direction of the force. What amount work is done?
A: 50 Joule
B: 15 Joule
C: 5 Joule
D: 0 Joule

Answer 1

Work done is given by

W=FS cos theta

As the object moves perpendicular to the direction of force

theta=90°

Cos 90=0

Hence the work done is zero

I hope this helps ( ╹▽╹ )

Answer 2

Answer:

The amount of work done by the object is 0 Joule.i.e.option(D).

Explanation:

The amount of work done by the object is given as,

$W=Fdcos\theta$     (1)

Where,

W=amount of work done

F=force applied to an object

d=displacement of an object

θ=angle between force and displacement

From the question we have,

F=5N

d=10

θ=90°      

(as the object moves in the perpendicular direction of the force)

By substituting the required values in equation (1) we get;

$W=5\times 10\times cos90\textdegree$

$W=0$                 ($cos90\textdegree=0$)

Hence, the amount of work done by the object is 0 Joule.i.e.option(D).