Question

Due to application of force both blocks move together. Each block exerts a force of 6 N on each other. Weight of blocks is 1kg and 0.5kg. The acceleration of the blocks will be

(A) 3 m/s2
(B) 6 m/s2
(C) 9 m/s
(D) 12 m/s2​

Answer 1

Answer:

answer may be B) 6m/s2...........thank you

Answer 2

The magnitude of the acceleration is 6 m/s².

(A) is correct option

Explanation:

Given that,

Force = 6 N

Mass of first block = 1 kg

Mass of second block = 0.5 kg

We need to calculate the acceleration

Using formula of force

$F-mg=ma$

$a=\dfrac{F-(m_{1}+m_{2})g}{(m_{1}+m_{2})}$

Put the value into the formula

$a=\dfrac{6-1.5\times10}{1.5}$

$a=-6\ m/s^2$

Hence, The magnitude of the acceleration is 6 m/s².

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Topic : acceleration

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