due to heavy flood in a state thousands were rendered homeless , 50 schools collectively offered to state government to provide place and the canvas for 1500 tents to be fixed . the lower part of each tent is cylindrical of radius 2.8 m and height 3.5 m with conical upper part of same radius and height 2.1 m .if the canvas used to make tents cost rs 120 per sq km , find the amount shared by each school to set up the tents?
Answers
Answered by
555
This was the question that had come in Class X Board 2016 today.
Answer -
CSA of Cylinder = 2*22/7*2.8*3.5 = 61.6 sq. cm
Slant Height of Cone = = = 3.5 cm
Hence, CSA of Cone = 22/7*2.8*3.5 = 30.8 sq. cm
Total Area of 1 Tent = 61.6 + 30.8 = 92.4 sq. cm
Rate of Canvas = ₹120 per sq. metre
Number of Tents = 1500
Number of School to share the cost = 50
Hence, the amount contributed by each school = [1500/50]*[120*92.4] = ₹332640
Value - Humanitarian & Proactive efforts are shown by students and teachers :P
Hope this helps...
Answer -
CSA of Cylinder = 2*22/7*2.8*3.5 = 61.6 sq. cm
Slant Height of Cone = = = 3.5 cm
Hence, CSA of Cone = 22/7*2.8*3.5 = 30.8 sq. cm
Total Area of 1 Tent = 61.6 + 30.8 = 92.4 sq. cm
Rate of Canvas = ₹120 per sq. metre
Number of Tents = 1500
Number of School to share the cost = 50
Hence, the amount contributed by each school = [1500/50]*[120*92.4] = ₹332640
Value - Humanitarian & Proactive efforts are shown by students and teachers :P
Hope this helps...
Answered by
112
Answer:
This was the question that had come in Class X Board 2016 today.
Answer -
CSA of Cylinder = 2*22/7*2.8*3.5 = 61.6 sq. cm
Slant Height of Cone = = = 3.5 cm
Hence, CSA of Cone = 22/7*2.8*3.5 = 30.8 sq. cm
Total Area of 1 Tent = 61.6 + 30.8 = 92.4 sq. cm
Rate of Canvas = ₹120 per sq. metre
Number of Tents = 1500
Number of School to share the cost = 50
Hence, the amount contributed by each school = [1500/50]*[120*92.4] = ₹332640
Value - Humanitarian & Proactive efforts are shown by students and teachers :P
Hope this helps...
Similar questions