Due to heavy floods in a state, thousands were rendered homeless. 50 schools collectively
offered to the state government to provide place and the canvas for 1500 tents to be fixed by the
government and decided to share the whole expenditure equally. The lower part of each tent is
cylindrical of base radius 2.8 m and height 3.5 m, with conical upper part of same base radius
but of height 2.1 m. If the canvas used to make the tents costs Rs 120 per sq.m, find the amount
shared by each school to set up the tents. What value is generated by the above problem?
[Use π=22/7] PLEASE HELP ME FRIENDS
Answers
Answer:otal area of each Tent (Cylinder) =2πrh
=2×
22
7
×2.8×3.5
=61.6 m2
Area of conical upper part (cone) = πrl
=
22
7
×2.8×
√
2.12+2.82
=30.8 m2
Area of 1500 tents = Area of cylinder + Area of cone
=61.6+30.8
=92.4 m2
Cost of making Tent = Rs. 120 per m2
Total money cost for canvas =120×90.4
= Rs. 11088
Amount shared by each school =
Total amount
Number of school
=
11088
50
= Rs. 221.76
Therefore, the amount shared by each school to set up the tents = Rs. 221.76=Rs.222 (approx)otal area of each Tent (Cylinder) =2πrh
=2×
22
7
×2.8×3.5
=61.6 m2
Area of conical upper part (cone) = πrl
=
22
7
×2.8×
√
2.12+2.82
=30.8 m2
Area of 1500 tents = Area of cylinder + Area of cone
=61.6+30.8
=92.4 m2
Cost of making Tent = Rs. 120 per m2
Total money cost for canvas =120×90.4
= Rs. 11088
Amount shared by each school =
Total amount
Number of school
=
11088
50
= Rs. 221.76
Therefore, the amount shared by each school to set up the tents = Rs. 221.76=Rs.222 (approx)
Step-by-step explanation: