Question

Due to some floods, some welfare associations jointly requested the government to get 100 tents fixed immediately and offered to contribute 50% of the cost. If the lower part of each tent is of the form of a cylinder of diameter 4.2 m and height 4 m with the conical upper part of same diameter but of height 2.8 m, and the canvas to be used costs 100 per square metre, find the amount the associations will have to pay. What values are shown by these associations?

▩it's very urgent !!!​

Answer 1

Answer:-

• Radius of the cylinder, r = 2.1 m.
• Height of the cylinder, h = 4 m.
• Radius of the cone radius of the cylinder = 2.1 m.
• Height of the cone, H = 2.8 m.
• Slant height of the cone,

$\sf \: l = \sqrt{{ {r}^{2} } + {H}^{2}}$

$\sf \: l = \sqrt{{ {(2.1)}^{2} } + {(2.8)}^{2}}$

$\sf \: l = \sqrt{4.41 + 7.84} \: m$

$\sf l = \sqrt{12.25} \: m$

Area of the canvas required for each tent = curved surface area of the cylinder + curved surface area of the cone

$\sf \longrightarrow 2\pi rh + \pi rl$

$\sf \longrightarrow [(2 \times \frac{22}{7} \times 2.1 \times 4) + ( \frac{22}{7} \times 2.1 \times 3.5) ] \: {m}^{2}$

$\sf \longrightarrow (52.8 + 23.1) \: {m}^{2}$

$\sf \longrightarrow 75.9 \: {m}^{2}$

Total area of the canvas required for 100 tents

$\sf \longrightarrow (75.9 \times 100) m²$

$\sf \longrightarrow 7590 \: {m}^{2}$

Total cost of 100 tents

$\sf \longrightarrow ₹ \: (7590 \times 100)$

$\sf \longrightarrow ₹ \: 759000$

Amount to be paid by the associations

$\sf \longrightarrow 50\% \: of \: ₹ \: 759000$

$\sf \longrightarrow ₹(\frac{50}{100} \times 759000)$

$\sf \longrightarrow ₹ \: 379500$

Hence, the associations will have to pay 379500.

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$\sf\small{ \underline{\underline\red{ \pmb{Values \: shown \: We \: must:-}}}}$

• help the people in need
• donate a part of our income to charity
• join hands together for a noble cause like community service.