Question

due to some frictional forces . velocity of a body reduces from 10 m/sec to 6 m/sec . the percentage loss in his K.E comes out ​

Answer 1

Answer:

K.E before = m(10²)/2

K.E after = m(6²)/2

loss in K.E is m/2(100-36)=64m/2

percentage loss is (64m/2)/(100m/2)×100

=>64%