Math, asked by Yolobolo, 1 year ago

Due to sudden floods, some welfare associations jointly requested the government to get 100 tents fixed immediately and offered to contribute 50% of the cost. If the lower part of each tent is in the form if a cylinder of diameter 4.2m, and height is 4m with a conical upper part of same diameter but of height 2.8m and the canvas to be used cost RS.100 per sq.m. Find the amount the association will have to pay.



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Answers

Answered by Reub3n
108
Cone, h = 2.8 , r = 2.1
L square = h square + r square
= 2.8 square + 2.1 square
Therefore, L = √12.25
= 3.5 cm

Area of canvas required for 1 tent
= 2πrh + πrl
= 2π × 2.1 × 4 + π × 2.1 × 3.5
= 16.8 π + 7.35 π
= 24.15 π
= 24.15 × 22/7 = 75.9m square

Therefore, Area of canvas required for 100 tents = 75.9 × 100
= 7590 m square

Cost of 1 m square = Rs.100
Therefore, cost of 7590 m square
= 7590×100
= Rs.759000

Amount association has to pay
= 759000 × 50/100
= Rs.379000

You're welcome :)

Yolobolo: tnks for putting in effort for this answer, you r the best thanks
Reub3n: Haha, you're always welcome bud
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Answered by Anonymous
38
Hey mate ^_^

=======
Answer:
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Given:

 Height\: of:-

=> Cylindrical part  = 4\:m

=> Conical part  = 2.8\:m

 Diameter \:of:-

=> Cylindrical part = 4.2 \:m

=> Conical part =4.2\:m

 Radius\: of:-

=> Cylindrical part = 2.1 \:m

=> Conical part =2.1\:m

 Now,

Surface Area of tent = C. S. A of cylindrical part + C. S. A of conical part

 We\: know,

C. S. A. of cylinder = 2\pi \:r\:h

 So,

C. S. A. of cylindrical part

 = 2 \times \frac{22}{7} \times 2.1 \times 4 \\

 = 2 \times 22 \times 0.3 \times 4 \\

 = 52.80m^{2}

 And,

C. S. A. of cone =\pi\:r\:l

Where, l \: = \sqrt{h^{2} + r ^{2} }

 So,

C. S. A. of conical part

 = \frac{22}{7} \times 2.1 \times \sqrt{2.8 ^{2} + 2.1^{2} } \\

 = 22 \times 0.3 \times \sqrt{7.84 + 4.41} \\

 = 6.6 \times \sqrt{12.25} \\

 = 6.6 \times 3.5 \\

 = 23.10m^{2}

Surface area of tent

 = 52.80 + 23.10 \\

 = 75.90m^{2}

 Now,

Surface area of 100 tents

 = 100 \times 75.90 \\

 = 7590m^{2}

 And,

Rate of canvas is  100per square meter.

 So,

Cost of 100 tents

 = 100 \times 7590 \\

 = 759000

 And,

Association offered 50% of the cost.

 Now,

Amount paid by association

 = 50\% \: of \: 759000

 = \frac{759000 \times 50}{100} \\

 = \frac{759000}{2} \\

 = 379500

Therefore,

Answer:  Rs. 375900

#Be Brainly❤️
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