due to the presence of a point charge at the centre of a spherical Gaussian surface of diameter a, 10 to the power 6 Newton metre square by full amount of electric flux passes through it.keeping the point charge at the centre the Gaussian surface is change to a cubical Gaussian surface of a side a the flux through the new gussain surface will be how much?
Answers
The flux through the new Gaussian surface is 10^6 Nm².
Given:
Spherical Gaussian surface flux of 10^6 Nm².
To Find:
The flux through the new Gaussian surface.
Solution:
"Gauss's law for electricity states that the electric flux Φ across any closed surface is proportional to the net electric charge q enclosed by the surface; that is, Φ = q/ε0, where ε0 is the electric permittivity of free space and has a value of 8.854 × 10–12 square coulombs per newton per square meter."
When the Spherical Gaussian surface is changed to a cubical Gaussian surface. In both cases, the point charge is kept at the center of the Gaussian surface.
∴ The electric flux of spherical Gaussian surface = Electric flux of cubical Gaussian surface.
Hence, The electric flux of cubical Gaussian surface = 10^6 Nm²
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