Question

due to the reduction of 16⅔% in the price of sugar, a man is able to buy 1200 g more sugar for Rs 288 . The reduced Rate of the sugar in (RS./kg ) is

1) 36
2)40
3)44
4)48

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Answer 1

Answer:

40 I am not sure what to do

Answer 2

Reduced rate = 40 Rs/kg

Step-by-step explanation:

We assume that;

• The rate of sugar = x Rs/kg

• Reduced rate = $x - 16\dfrac{2}{3} \ \% \ of \ x$

                                = $x - \dfrac{50}{3} \ \% \ of \ x$  

Therefore, Reduced rate =$x - \left (\dfrac{50}{3} \times \dfrac{1}{100} \times x \right )$

• Reduced rate = $\dfrac{5x}{6}$ Rs/kg

• Now, the quantity of sugar bought for the Rs 288 at the rate of x Rs/kg = $\dfrac{288}{x}$kg  ..........(1)

• The quantity of sugar bought for the Rs 288 at the rate of $\dfrac{5x}{6} Rs/kg = \dfrac{288}{\dfrac{5x}{6}} \ kg$    ..........(2)

Now, we can understand that the difference of (2) and (1) is 1.2 kg (given).

• $\dfrac{288}{\dfrac{5x}{6}} - \dfrac{288}{x} = 1.2$

          $\dfrac{288\times 6}{5x} - \dfrac{288}{x} = 1.2$

By solving, we get.

• $\dfrac{6\times 288 - 1440}{5\times 1.2}$ = x

• x = 48 Rs/kg

So, Reduced rate = $\dfrac{5x}{6}$ = 40 Rs/kg