due to traffic on the road , a bus runs at a speed that is two-elevenths of its actual speed and covers a distance of 18.7km in 2 hours, 20 minutes and 15 seconds. if the traffic on the road is cleared, in how much time will the bus cover a distance of 56km?
Answers
Solution :-
Let us assume that, the actual speed of bus is x km/h .
so,
→ Speed = (2x/11) km/h
→ Distance covered = 18.7 km
→ Time taken = 2 hours 20 minutes and 15 seconds = 2 + 20/60 + 15/3600 = 2 + 1/3 + 1/240 = (480 + 80 + 1)/240 = (561/240) = (187/80) hours
then,
→ Speed * time = Distance
→ (2x/11) * (187/80) = 18.7
→ (17x/40) = 18.7
→ x = (18.7 * 40)/17
→ x = 44 km/h .
therefore,
→ Time taken to cover a distance of 56 km = Distance / speed = 56/44 = (14/11) = 1(3/11) hours .
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