dufferentiate sec5x with rescpect to x from the first principle
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Step-by-step explanation:
Differentiate using the chain rule, which states that
d
d
x
[
f
(
g
(
x
)
)
]
ddx[f(g(x))] is
f
'
(
g
(
x
)
)
g
'
(
x
)
f′(g(x))g′(x) where
f
(
x
)
=
sec
(
x
)
f(x)=sec(x) and
g
(
x
)
=
5
x
g(x)=5x.
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sec
(
5
x
)
tan
(
5
x
)
d
d
x
[
5
x
]
sec(5x)tan(5x)ddx[5x]
Differentiate.
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