Question

DUIT
JULUI
14. The area of a rectangle is 650 cm" and its width is 13 cm. Find the perimeter of the
rectangle. Also, calculate its area if the length of the rectangle is 15% more than its
width.
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Answer 1

Step-by-step explanation:

Given,

area of rectangle is 650cm

width of the rectangle is 13 cm

Here we can find length -

area of rectangle = length *breadth

650 = length * 13

650/13 = length

50 = length

perimeter of the rectangle = 2*(length + breadth)

= 2 ( 50+13)

=2(63)

=126

Answer 2

Answer:

The perimeter is 126 cm. The new area is 194.35 cm²

Step-by-step explanation:

area of a rectangle = 650 cm

width = 13 cm

length = ?

As we know,

area of rectangle = lenght × breadth

→ 650 = length × 13

→ length = 650/13

→ length = 50 cm

perimeter = 2(lenght + breadth)

= 2(50 + 13)

= 2 × 63

= 126

perimeter = 126 cm

according to que

if lenght is 15% more than breadth

i.e. length= (15/100) × 13

i.e. length = (15×13)/100

i.e. length = 1.95

therefore new length = 1.95 + 13

new length = 14.95 cm

new area = 14.95 × 13

new area = 194.35 cm²