Question

Durga wants to polish a circular table top of diameter 2.8.m. Find the cost of polishing if the rate of
polishing is 25 per sq.m.​

Answer 1

Answer:

Radius=Diameter/2

=2.8/2

=1.4m

Area of table top=πr^2

=22/7×1.4×1.4

= 6.16sq.m

Cost of polishing the table top=6.16×25

=154

Ans- rs.154

Answer 2

The cost of polishing if the rate of  polishing is 25 per sq.m.​ is Rs.154

Step-by-step explanation:

Diameter of circular table = 2.8 m

Radius of circular table =$\frac{Diameter }{2}=\frac{2.8}{2}=1.4 m$

Area of circular table =$\pi r^2$

                                   = $\frac{22}{7} \times 1.4^2$

                                   =$6.16 m^2$

Cost of polishing 1 sq.m. = Rs.25

Cost of polishing 6.16 sq.m. =$25 \times 6.16 =Rs.154$

Hence The cost of polishing if the rate of  polishing is 25 per sq.m.​ is Rs.154

#Learn more:

Find the cost of polishing a circular table top of diameter 2.2 m if the rate of polishing is 20​

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